本篇内容介绍了“Java怎么生成括号”的有关知识,在实际案例的操作过程中,不少人都会遇到这样的困境,接下来就让小编带领大家学习一下如何处理这些情况吧!希望大家仔细阅读,能够学有所成!
Given n pairs of parentheses, write a function to generate all combinations of well-formed
parentheses.
For example, given n = 3, a solution set is:
[
"((()))",
"(()())",
"(())()",
"()(())",
"()()()"
]
public class Solution {
public List<String> generateParenthesis(int n) {
ArrayList<String> result = new ArrayList<String>();
dfs(result, "", n, n);
return result;
}
/*
left and right represents the remaining number of ( and ) that need to be added.
When left > right, there are more ")" placed than "(". Such cases are wrong and the method stops.
*/
public void dfs(ArrayList<String> result, String s, int left, int right){
if(left > right) //因为从left开始减一,所以left不可能小于right
return;
if(left==0&&right==0){
result.add(s);
return;
}
if(left>0){
dfs(result, s+"(", left-1, right); //
}
if(right>0){
dfs(result, s+")", left, right-1);
}
}
}
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