本篇文章为大家展示了怎么在Python中绘制一个数码晶体管日期,内容简明扼要并且容易理解,绝对能使你眼前一亮,通过这篇文章的详细介绍希望你能有所收获。
代码:
import turtle, time
def drawLine(draw):
turtle.pendown() if draw else turtle.penup()
turtle.fd(40)
turtle.right(90)
def drawDight(dight):
drawLine(True) if dight in [2, 3, 4, 5, 6, 8, 9] else drawLine(False)
drawLine(True) if dight in [0, 1, 3, 4, 5, 6, 7, 8, 9] else drawLine(False)
drawLine(True) if dight in [0, 2, 3, 5, 6, 8, 9] else drawLine(False)
drawLine(True) if dight in [0, 2, 6, 8] else drawLine(False)
turtle.left(90)
drawLine(True) if dight in [0, 4, 5, 6, 8, 9] else drawLine(False)
drawLine(True) if dight in [0, 2, 3, 5, 6, 7, 8, 9] else drawLine(False)
drawLine(True) if dight in [0, 1, 2, 3, 4, 7, 8, 9] else drawLine(False)
turtle.right(180)
turtle.penup()
turtle.fd(20)
def drawDate(date):
turtle.pencolor("red")
for i in date:
if i == '-':
turtle.write('年', font=("微软雅黑", 32, "normal"))
turtle.pencolor("green")
turtle.fd(80)
elif i == '=':
turtle.write('月', font=("微软雅黑", 32, "normal"))
turtle.pencolor("blue")
turtle.fd(80)
elif i == '+':
turtle.write('日', font=("微软雅黑", 32, "normal"))
turtle.pencolor("red")
turtle.fd(80)
elif i == '/':
turtle.write('时', font=("微软雅黑", 32, "normal"))
turtle.pencolor("green")
turtle.fd(80)
elif i == '*':
turtle.write('分', font=("微软雅黑", 32, "normal"))
turtle.pencolor("blue")
turtle.fd(80)
elif i == '.':
turtle.write('秒', font=("微软雅黑", 32, "normal"))
turtle.fd(80)
else:
drawDight(eval(i))
if __name__ == '__main__':
# turtle.setup() 我用的是pycharm,所以没有设置画布,idle下需要设置
turtle.penup()
turtle.fd(-350)
turtle.pensize(5)
turtle.speed(1000) # 速度再大也没感觉了
drawDate(time.strftime('%Y-%m=%d+', time.localtime()))
# 这里千万不要用time.gmtime()),获取的是UTC时区(0时区)的struct_time
# 踩了半天坑
turtle.right(90)
turtle.fd(120)
turtle.right(90)
turtle.fd(660)
turtle.right(180)
drawDate(time.strftime('%H/%M*%S.', time.localtime()))
turtle.hideturtle()
turtle.done()
上述内容就是怎么在Python中绘制一个数码晶体管日期,你们学到知识或技能了吗?如果还想学到更多技能或者丰富自己的知识储备,欢迎关注天达云行业资讯频道。